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  • An aluminium rod with Young's modulus  <img alt="Y = 7.0 \times 10 ^{10} N/m^{2}" src="https://entrancecorner.oncodecogs.com/gif.latex?Y%20%3D%207.0%20%5Ctimes%2010%20%5E%7B10%7D%20N/

An aluminium rod with Young's modulus  Y = 7.0 \times 10 ^{10} N/m^{2} undergoes elastic strain of 0.04%. The energy per unit volume stored in the rod in SI unit is:

Option: 1

5600


Option: 2

2800


Option: 3

11200


Option: 4

8400


Answers (1)

best_answer

Aluminium rod Young’s modulus
\mathrm{y}=7.0 \times 10^{10} \frac{\mathrm{N}}{\mathrm{m}^2}
strain 0.04%
strain = \frac{0.04}{100}
Energy per unit volume = \frac{1}{2} stress \times strain
= \frac{1}{2} y strain \times strain
= \frac{1}{2}y\left ( strain \right )^{2}
=\frac{1}{2} \times 7 \times 10^{10} \times\left(\frac{0.04}{100}\right)^2
Energy per unit volume = 5600 \frac{J}{ m^{3}}

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