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  • An astronaut  is approaching the moon.He sends a tadio signal of frequency <img alt="\mathrm{5\times 10^{9}Hz}" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cmathrm%7B5%5Ctimes%

An astronaut  is approaching the moon.He sends a tadio signal of frequency \mathrm{5\times 10^{9}Hz}. and finds that the frequency shift in echo received is \mathrm{ 10^{3}Hz}. Calculate the speed of his approch - 

Option: 1

40 m/s


Option: 2

30 m/s


Option: 3

10 m/s


Option: 4

85 m/s


Answers (1)

best_answer

The Frequency shift as observed on moon.

\mathrm{ \frac{\Delta f}{f}=\frac{v}{c} \Rightarrow \Delta f=\frac{v}{c} f }

Now, moon becomes siurce of frequency \mathrm{ f_1=(f+\Delta f) }

The shift in frequency in reflected light is observed,

\mathrm{ \Delta f=\frac{v f}{c} }

therefore , total shift observed \mathrm{20\; f=2f\; \frac{V}{C}}

\mathrm{ \begin{aligned} 10^3 & =2 \times 5 \times 10^3 \times \frac{V}{3 \times 10^8} \\ V & =30 \mathrm{~m} / \mathrm{s} . \end{aligned} }

 

Posted by

shivangi.bhatnagar

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