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An automobile travelling with a speed of 60 km/h, can brake to stop within a distance of 20 m. If the car is going twice as fast, i.e. 120 km/h, the stopping distance will be

Option: 1

20 m


Option: 2

40 m


Option: 3

60 m


Option: 4

80 m


Answers (1)

best_answer

Let  a be the retardation for both the vehicles

For automobile \nu ^{2}= u^{2}-2\: as

\therefore u{_{1}}^{2}-2as= 0

\Rightarrow u{_{1}}^{2}=2as

Similarly for car, u{_{2}}^{2}=2as_{2}

\therefore \: \: \: \left ( \frac{u_{2}}{u_{1}} \right )^{2}= \frac{s_{2}}{s_{1}}\Rightarrow \left ( \frac{120}{60} \right )^{2}= \frac{s_{2}}{20}

or\: \: \: s_{2}= 80 m

Posted by

Ritika Kankaria

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