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  • An electric bulb rated for 500 W at 100 V is used in a circuit having a 200 V supply. The resistance R that must be put in series with the bulb, so that the bulb draws 500 W is<div class='qna-o

An electric bulb rated for 500 W at 100 V is used in a circuit having a 200 V supply. The resistance R that must be put in series with the bulb, so that the bulb draws 500 W is

Option: 1

100 \, \, \Omega


Option: 2

50\, \, \Omega


Option: 3

20 \, \, \Omega


Option: 4

10\, \, \Omega


Answers (1)

best_answer

In order that the bulb draws 500 W, there should be 100 V applied across it. The remaining 100 V should be dropped in the series resistance R. Now, the current in the bulb is given by

P=V . I

\therefore \quad I=\frac{P}{V}=\frac{500}{100}=5 \mathrm{~A}

The same current flows through R. Hence,

R=\frac{V}{I}=\frac{100}{5}=20 \Omega

Hence, answer (c) is correct.

Posted by

sudhir.kumar

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