Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • An electric heater is designed to operate in 100 V main with a power output of 1000 W. When it is connected to a 25 V source, power output is:Option: 1

An electric heater is designed to operate in 100 V main with a power output of 1000 W. When it is connected to a 25 V source, power output is:

Option: 1

40 W 


Option: 2

100 W


Option: 3

62.5 W 


Option: 4

250 W


Answers (1)

best_answer

The resistance of the bulb rated 100V, 1000W is

P=\frac{V^2}{R} \text { or } R=\frac{V^2}{P}=\frac{100 \times 100}{1000}=10 \Omega

Hence when the bulb is connected to 25 volt source the output power is

\mathrm{P}=\frac{\mathrm{V}^2}{\mathrm{R}}=\frac{25 \times 25}{10}=62.5 \text { Watts }

 

Posted by

Deependra Verma

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2025 response sheet errors: Delhi HC allows student to apply for JEE Adv, seeks NTA explanation
anam-khan

Four Kashmiri girls defy the odds, score 99+ percentile in JEE Main 2025
anam-khan

JEE, NEET, CUET coaching centres: Assam, Rajasthan have framed laws, but will they work?

Latest Question