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  • An electromagnetic wave, going through vacuum is described by <img alt="\mathrm{E=E_0 \sin (k x-\omega t) }" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cmathrm%7BE%3DE_0%20%5Csin%2

An electromagnetic wave, going through vacuum is described by \mathrm{E=E_0 \sin (k x-\omega t) } Which of the following is independent of wavelength?

Option: 1

k


Option: 2

\omega


Option: 3

k / \omega


Option: 4

k \omega


Answers (1)

best_answer

Here, \mathrm{k x=\theta\, \, or\, \, k=\theta / x }
And \mathrm{\omega t=\theta_0 or \omega=\theta_0 / t \therefore k / \omega=t / x=1 /(x / t)=\frac{1}{v} }, where v is the velocity of electromagnetic wave, which is independent of wavelength of wave but depends upon the nature of medium of propagation of wave.

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avinash.dongre

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