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An electron collides with a fixed hydrogen atom in its ground state. Hydrogen atom gets excited and the colliding electron loses all its kinetic energy. Consequently the hydrogen atom may emit a photon corresponding to the largest wavelength of the Balmer series. The K.E. of colliding electron will be
 

Option: 1

10.2 \mathrm{eV}


Option: 2

1.9 \mathrm{eV}


Option: 3

12.1 \mathrm{eV}


Option: 4

13.6 \mathrm{eV}


Answers (1)

best_answer

Kinetic energy of electron = 13.6\left[\frac{1}{2^2}-\frac{1}{3^2}\right]=13.6 \times \frac{5}{36}=1.9 \mathrm{eV}

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vishal kumar

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