Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • An electron of mass me, initally at rest, mores through a certain distance in a uniform electric field in ltime .

An electron of mass me, initally at rest, mores through a certain distance in a uniform electric field in ltime t_{1}. A proton of mass m_{p}, also initially at rest, takes time t_{2} to move through an equal distance in this uniform electric field. Neglecting the effect of gravity, the ratio t_{2}/t_{1}  is nearly equal to-

Option: 1

1


Option: 2

\mathrm{\left(m_{p} / m_{c}\right)^{1 / 2}}


Option: 3

\mathrm{\left(m_{e} / m_{p}\right)^{1 / 2} }


Option: 4

\mathrm{2 m_{p} / 3 m_{e}}


Answers (1)

best_answer

Electrostatics force, \mathrm{Fe}=\mathrm{eE} (for both the particles)

But acceleration of the electron; \mathrm{a}_{\mathrm{e}}= \mathrm{Fe}/{\mathrm{me}}

Acceleration of proton, \mathrm{a_{p}=\mathrm{Fe} / \mathrm{mp}_{\mathrm{}}}

\mathrm{use, s=\frac{1}{2} \, a_{e} t_{1}^{2}=\frac{1}{2} \, a_{p} t_{2}^{2}}

\mathrm{\therefore \quad \frac{t_{2}}{t_{1}}=\sqrt{\frac{a_{e}}{a_{p}}}=\sqrt{\frac{m_{p}}{m_{e}}}} Ans

Posted by

Deependra Verma

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2026: JCECEB invites fresh applications for Jharkhand state merit list correction

Latest Question