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An emf of 0.08 \mathrm{~V}is induced in a metal rod of length 10 \mathrm{~cm} held normal to a uniform magnetic field of 0.4 \mathrm{~T},  when moves with a velocity of:

Option: 1

2 \mathrm{~ms}^{-1}


Option: 2

20 \mathrm{~ms}^{-1}


Option: 3

3.2 \mathrm{~ms}^{-1}


Option: 4

0.5 \mathrm{~ms}^{-1}


Answers (1)

best_answer

\varepsilon=\mathrm{Blv}
\Rightarrow 0.08=\mathrm{v} \times 0.4 \times \frac{10}{100}
\Rightarrow \mathrm{v}=2 \mathrm{~m} / \mathrm{s}

Posted by

Ajit Kumar Dubey

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