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An experiment is conducted to measure the diameter of a cylindrical object using a screw gauge. The main scale reading is 2.0 mm, and the circular scale reading is 42. The pitch of the screw gauge is 0.25 mm, and the least count of the instrument is 0.01 mm. Determine the diameter of the cylindrical object.

Option: 1

0.605 mm


Option: 2

0.605 cm


Option: 3

6.05 mm


Option: 4

0.0605 mm


Answers (1)

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Given values:

Main scale reading (M) = 2.0 mm
Circular scale reading (C) = 42
Pitch of the screw gauge (P) = 0.25 mm
Least count (LC) = 0.01 mm

The total reading of the screw gauge can be calculated by adding the main scale reading to the product of the circular scale reading and the least count:

                Total reading = M + (C * LC)

Step 1: Calculate the total reading of the screw gauge:

            Total reading = 2.0 mm + (42 * 0.01 mm) = 2.0 mm + 0.42 mm = 2.42 mm

The diameter of the cylindrical object can be calculated using the formula:

               Diameter = Total reading * P

Step 2: Calculate the diameter:

                Diameter = 2.42 mm * 0.25 mm = 0.605 mm

The diameter of the cylindrical object is 0.605 mm.

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Riya

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