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An experiment succeeds twice as often as it fails.  The probability of at least 5 successes in the six trials of this experiment is :

Option: 1

\frac{240}{729}


Option: 2

\frac{192}{729}


Option: 3

\frac{256}{729}


Option: 4

\frac{496}{729}


Answers (1)

best_answer

Let the probability of failure P=x

So the probability of success=2x

Hence, x=\frac{1}{3}

P(5 Success)^{6}C_{5}\times (\frac{2}{3})^{5}\times (\frac{1}{3}) = \frac{192}{256}

P(6 Success)^{6}C_{6}\times (\frac{2}{3})^{6} = \frac{64}{256}

P(atleast 5 Success) = P(5 Success) + P(6 Success)

=\frac{256}{729}

Posted by

Kuldeep Maurya

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