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An ideal coil of 15 H is connected in series with a resistance of 5\Omega and battery of 5V. 6 second after the connection is made, the current flowing in ampere in the circuit is

 

Option: 1

1-e^{-1}
 


Option: 2

1-e^{-2}


Option: 3

1-e^{-1/2}


Option: 4

e^{-3}


Answers (1)

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The correct option is (2)

\begin{aligned} i=\tau_{0}\left(1-e^{-t / t}\right) & \\ \tau=\frac{L}{R}=\frac{15}{5}=3 & \end{aligned}

\begin{aligned} &i=i_{0}\left(1-e^{-6 / 3}\right)=i_{0}\left(1-e^{-2}\right) \\ &i_{0}=\frac{v}{R}=\frac{5}{5}=14 \\ &i=\left(1-e^{-2}\right) \end{aligned}

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