Get Answers to all your Questions

header-bg qa

An inductance L and a resistance R are first connected to a battery. After some time the battery is disconnected but L and R remain connected in a closed circuit. Then the current reduces to 37% of its initial value in:

Option: 1

RL second


Option: 2

 \mathrm{\frac{R}{L}}second


Option: 3

\mathrm{\frac{L}{R}} second


Option: 4

\mathrm{\frac{1}{LR}}second


Answers (1)

best_answer

Time constant, \mathrm{\tau=\frac{L}{R}}

It is the time interval during which the current after opening an inductive circuit falls to 37% of its maximum value.

Posted by

shivangi.bhatnagar

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE