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An ionic atom equivalent to hydrogen atom has wavelength equal to 1/4 of the wavelengths of hydrogen lines. The ion will be

Option: 1

\mathrm{He}^{+}


Option: 2

\mathrm{L i^{++}}


Option: 3

\mathrm{Ne}^{9+}


Option: 4

\mathrm{Na}^{10+}


Answers (1)

best_answer

\mathrm{\bar{v} \propto \frac{1}{\lambda} \propto Z^2 \Rightarrow \lambda Z^2= \, constant \, \Rightarrow \lambda=\frac{\lambda}{4} Z^2 \Rightarrow Z=2}

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Ritika Jonwal

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