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  • An object is placed at a distance of from a concave mirror of radius of curvature <img

An object is placed at a distance of \mathrm{10\ cm} from a concave mirror of radius of curvature \mathrm{0.6\ m}. Which of the following statements is incorrect?

Option: 1

The image is formed at a distance of \mathrm{15\ cm} from the mirror


Option: 2

The image formed is virtual


Option: 3

The image is 0.5 times the size of the object


Option: 4

The image is 1.5 times the size of the object


Answers (1)

best_answer

\mathrm{Here\ \mathrm{f}=-\frac{0.6}{2}=-0.3 \mathrm{~m}=-30 \mathrm{~cm}, \mathrm{u}=-10 \mathrm{~cm}}\\ \mathrm{As,\ \frac{1}{\mathrm{v}}+\frac{1}{\mathrm{u}}=\frac{1}{\mathrm{f}}\ \ \ \quad or \frac{1}{\mathrm{v}}+\frac{1}{-10}=\frac{1}{-30}}
\mathrm{\begin{aligned} & \frac{1}{\mathrm{v}}=\frac{1}{10}-\frac{1}{30}=\frac{3-1}{30} \quad \text { or } \mathrm{v}=\frac{30}{2} \mathrm{~cm}=15 \mathrm{~cm} \\ & \therefore \mathrm{m}=-\frac{\mathrm{v}}{\mathrm{u}}=-\frac{15}{-10}=1.5 \end{aligned}}
Object is placed between principal focus and pole. So, the image is virtual and erect.

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Anam Khan

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