An object of uniform density is allowed to float in water kept in a beaker. The object has triangular cross-section as shown in the figure. If the water pressure measured at three point A, B and C below the object are PA, PB and PC respectively. Then-
PA > PB > PC
PA > PB < PC
PA = PB = PC
PA = PB < PC
In horizontal direction, pressure remains constant unless it is accelerated. It means PA = PB = PC.
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