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An object of uniform density is allowed to float in water kept in a beaker. The object has triangular cross-section as shown in the figure. If the water pressure measured at three point A, B and C below the object are P_A, P_B and P_C respectively. Then-

Option: 1
P_A > P_B > P_C

Option: 2
P_A > P_B < P_C

Option: 3
P_A = P_B = P_C

Option: 4
P_A = P_B < P_C

Answers (1)

best_answer

In horizontal direction, pressure remains constant unless it is accelerated. It means P_A = P_B = P_C.

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Kuldeep Maurya

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