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An object of uniform density is allowed to float in water kept in a beaker. The object has triangular cross-section as shown in the figure. If the water pressure measured at three point A, B and C below the object are PA, PB and PC respectively. Then-

Option: 1

PA > PB  > PC


Option: 2

PA > PB < PC


Option: 3

PA = PB = PC


Option: 4

PA = PB < PC


Answers (1)

best_answer

In horizontal direction, pressure remains constant unless it is accelerated. It means PA = PB = PC.

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Kuldeep Maurya

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