Get Answers to all your Questions

header-bg qa

An unstable particle of rest energy \mathrm{1000\ \mathrm{Mer}} decays into a \mathrm{\mu} - meson and neutrino, with a mean life time of \mathrm{10^{-8}\ \mathrm{sec}}, when at rest. The mean decay distance, in metre, when the particle has a momentum of \mathrm{1000\ \mathrm{MeV} / \mathrm{c}} is -

Option: 1

\mathrm{3}


Option: 2

\mathrm{6}


Option: 3

\mathrm{9}


Option: 4

\mathrm{12}


Answers (1)

best_answer

Energy of \mathrm{1000\ Me\ v/c} category of neutrio
 \mathrm{=} momentum \mathrm{xc= \frac{1000}{c}\times c=1000\ MeV}
 Half life for \mathrm{1000\ MeV} neutrio \mathrm{10^{-8}\ sec.}
\mathrm{\therefore } Distance travelled in \mathrm{ 10^{-8}\ s }.
\mathrm{ \begin{aligned} & =10^{-8} \times\left(3 \times 10^8\right) \\ & =3 \times 10^0=3 \mathrm{~m} \end{aligned} }

Posted by

manish painkra

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE