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  • An urn contains 5 red and 7 green balls. ball is drawn at random and its colour is noted. The ball is

An urn contains 5 red and 7 green balls. \mathrm{A} ball is drawn at random and its colour is noted. The ball is placed back into the urn along with another ball of the same colour. The probability of getting a red ball in the next draw is

Option: 1

\frac{65}{156}


Option: 2

\frac{67}{156}


Option: 3

\frac{79}{156}


Option: 4

\frac{89}{156}


Answers (1)

best_answer

Case I - If 1^{\text {st }} draw is red ball the urn contains 6 R & 7G balls for 2^{\text {nd }} draw.

Case II- If 1^{\text {st }} draw is G ball the urn contains 5R & 8G  balls for 2^{\text {nd}} draw.

So Req. Prob

=\frac{5}{12}\times \frac{6}{13}+\frac{7}{12}\times \frac{5}{1}
(1 st draw)(2nd draw)(1st draw)(2nd draw)

=\frac{65}{156}

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Gunjita

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