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Area of the triangle formed by the line \mathrm{x+y=3} and angle bisector of the pair of straight lines \mathrm{x^{2}-y^{2}+2 y=1} is

Option: 1

2 sq.units


Option: 2

4 sq.units


Option: 3

 6 sq.units


Option: 4

8 sq.units


Answers (1)

best_answer

The equation \mathrm{x^{2}-y^{2}+2 y=1} represents \mathrm{x-y+1=0} and \mathrm{x+y-1=0} Hence equation of their angle bisector are \mathrm{x=0} and \mathrm{y= 1}.

Hence (A) is the correct answer.

Posted by

mansi

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