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  • Arrange the following carbocations in order of their stability (Ph = Phenyl Group) <img alt="\dpi{100} \large \mathrm{PhCH_2^+, (Ph)_2CH^+ , (Ph)_3C^+, CH_3^+}" src="https://entrancecorne

Arrange the following carbocations in order of their stability (Ph = Phenyl Group)

\dpi{100} \large \mathrm{PhCH_2^+, (Ph)_2CH^+ , (Ph)_3C^+, CH_3^+}

Option: 1

\mathrm{ CH_3^+ > (Ph)_2CH^+>PhCH_2^+ >(Ph)_3C^+}


Option: 2

\large \mathrm{ (Ph)_3C^+> (Ph)_2CH^+>PhCH_2^+ > CH_3^+}


Option: 3

\mathrm{ CH_3^+ >PhCH_2^+ > (Ph)_2CH^+>(Ph)_3C^+}


Option: 4

\mathrm{ CH_3^+ > (Ph)_3C^+>PhCH_2^+ >(Ph)_2CH^+}


Answers (1)

best_answer

As we have learnt,

Greater the extent of resonance, greater is the stability of the carbocation

Hence, the stability order of the given carbocations is 

\large \mathrm{ (Ph)_3C^+> (Ph)_2CH^+>PhCH_2^+ > CH_3^+}

Therefore, the correct answer is (2)

Posted by

Pankaj Sanodiya

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