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Arrange the following solution in the decreasing order of pOH A) 0.01M \; HCl B) 0.01M \ NaOH C) 0.01M\ CH_{3}COONa D) 0.01M \; NaCl
Option: 1 B>C>D>A
 
Option: 2 B>D>C>A
Option: 3 A>D>C>B  
Option: 4 A>C>D>B

Answers (1)

best_answer

pOH + pH = 14

If pH is low(means more acidic) then pOH is high.

Thus, acidic order: HCl > NaCl > CH_{3}COONa > NaOH.

Then the order of pOH will be:

A > D > C > B.

Therefore, Option(3) is correct.

Posted by

Kuldeep Maurya

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