Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • As per the given figure, two blocks each of mass  are connected to a spring of sprin

As per the given figure, two blocks each of mass \mathrm{ 250 \mathrm{~g}} are connected to a spring of spring constant \mathrm{ 2 \; \mathrm{Nm}^{-1}.} If both are given velocity \mathrm{v} in opposite directions, then maximum elongation of the spring is:

Option: 1

\mathrm{\frac{v}{2 \sqrt{2}}}


Option: 2

\mathrm{\frac{v}{2}}


Option: 3

\mathrm{\frac{v}{4}}


Option: 4

\mathrm{\frac{v}{\sqrt{2}}}


Answers (1)

best_answer

\mathrm{m=250 g=0.25 \mathrm{~kg}}
As the spring extends, the retarding force acts on the block
At maximum elongation, the speed & each block is zero By energy conservation,

\mathrm{T E_{\text {pritial }} =T E_{\text {final }} }

\mathrm{2\left(\frac{1}{2} m v^2\right) =\frac{1}{2} k x_m^2 }

\mathrm{0.25 \times v^2 =\frac{1}{2} \times 2 x_m^2 }

\mathrm{x_m =\frac{v}{2} }

Hence (2) is correct option.

Posted by

shivangi.shekhar

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

Amrita BTech Admission 2025: JEE Main-based registration deadline extended to August 30
anam-khan

DASA, CSAB Special round 2 seat allotment result 2025 declared on csab.nic.in

Latest Question