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  • As per the given figure, two blocks each of mass  are connected to a spring of sprin

As per the given figure, two blocks each of mass \mathrm{ 250 \mathrm{~g}} are connected to a spring of spring constant \mathrm{ 2 \; \mathrm{Nm}^{-1}.} If both are given velocity \mathrm{v} in opposite directions, then maximum elongation of the spring is:

Option: 1

\mathrm{\frac{v}{2 \sqrt{2}}}


Option: 2

\mathrm{\frac{v}{2}}


Option: 3

\mathrm{\frac{v}{4}}


Option: 4

\mathrm{\frac{v}{\sqrt{2}}}


Answers (1)

best_answer

\mathrm{m=250 g=0.25 \mathrm{~kg}}
As the spring extends, the retarding force acts on the block
At maximum elongation, the speed & each block is zero By energy conservation,

\mathrm{T E_{\text {pritial }} =T E_{\text {final }} }

\mathrm{2\left(\frac{1}{2} m v^2\right) =\frac{1}{2} k x_m^2 }

\mathrm{0.25 \times v^2 =\frac{1}{2} \times 2 x_m^2 }

\mathrm{x_m =\frac{v}{2} }

Hence (2) is correct option.

Posted by

shivangi.shekhar

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