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As shown in the figure, an ideal gas is taken through the cycle ABCA. If net heat supplied in the cycle is 3 J. The work done by the gas in the process A->B is (in J)

                     

Option: 1

-1


Option: 2

5


Option: 3

2


Option: 4

3


Answers (1)

best_answer

Process B->C at constant volume W_{BC}= 0

Process C->A at constant pressure W_{CA}= P\Delta V= 2(6-4)=4J

As volume of gas is increasing work done is positive.

As the entire process is cyclic.

so \Delta U=0

\Delta Q=\Delta W+\Delta U\Rightarrow W_{AB}+W_{BC}+W_{CA}

3=W_{AB}+0+4

W_{AB}=-1J

Posted by

Rishabh

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