Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • As shown in the figure, in an experiment to determine Young's modulus of a wire, the extension-load curve is plotted. The curve is a straight line passing through the origin and makes an angle

As shown in the figure, in an experiment to determine Young's modulus of a wire, the extension-load curve is plotted. The curve is a straight line passing through the origin and makes an angle of 45° with the load axis. The length of wire is 62.8cm and its diameter is 4 mm. The Young’s modulus is found to be x \times 10^4 \mathrm{Nm}^{-2}.The value of x is __________
                                          

Option: 1

5


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

\text{From graph}, \tan 45^{\circ}=\frac{\Delta l}{F} \Rightarrow \frac{\Delta l}{F}=1----(i) \\Also, \text{Young's modulus is given by}\ Y=\frac{F l}{A \Delta l}=\frac{l}{A} \times \frac{F}{\Delta l}=\frac{l}{A} \times 1$ $$ \begin{aligned} & \therefore Y=\frac{l}{A}=\frac{62.8 \times 10^{-2}}{\pi \times 4 \times 10^{-6}}=5 \times 10^4 \mathrm{Nm}^{-2} \\ & \therefore x=5 \end{aligned}

Posted by

seema garhwal

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2025 response sheet errors: Delhi HC allows student to apply for JEE Adv, seeks NTA explanation
anam-khan

Four Kashmiri girls defy the odds, score 99+ percentile in JEE Main 2025
anam-khan

JEE, NEET, CUET coaching centres: Assam, Rajasthan have framed laws, but will they work?

Latest Question