Browse by Stream
QnA
Home

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • Assume a right triangle ABC which sides are a,b,c and c is hypotenuse opposite of angle C of triangle ABC, than what is the value of <img alt="\frac{1}{\tan(A)}+\frac{1}{\tan(B)

Assume a right triangle ABC which sides are a,b,c and c is hypotenuse opposite of angle C of triangle ABC, than what is the value of

\frac{1}{\tan(A)}+\frac{1}{\tan(B)}

 

Option: 1

\frac{2c^2}{ab}


Option: 2

\frac{c^2}{ab}


Option: 3

\frac{ab}{c^2}


Option: 4

\frac{ab}{2c^2}


Answers (1)

best_answer

\frac{1}{\tan(A)}+\frac{1}{\tan(B)}={\cot(A)}+\cot(B)\\ =\frac{b}{a}+\frac{a}{b}\\ =\frac{a^2+b^2}{ab}\\ =\frac{c^2}{ab}

Posted by

Sayak

View full answer

Similar Questions

Latest Question