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Assuming that the silicon diode having resistance of\mathrm{20\Omega } , the current through the diode is (knee voltage 0.7 V)

Option: 1

0 mA


Option: 2

10 mA


Option: 3

6.5 mA


Option: 4

13.5 mA


Answers (1)

best_answer

Here diode is forward biased with voltage = 2 – 0 = 2V.

\mathrm{\begin{aligned} & V_B=V_{\text {knee }}+I R \\ & 2=0.7+I \times 200 \\ & \text { ( } \therefore \text { Total resistance }=180+20=200 \Omega \text { ) } \\ & \therefore \quad I=\frac{1.3}{200}=6.5 \mathrm{~mA} \end{aligned}}

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Riya

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