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At a given temperablue T, g ares Ne, Arr, Xe and kr o are found to deviate from ideal gas behaviour. Theirs equation of state in given as, \mathrm{p=\frac{R T}{V-b} al T}.
which gas will exhibit steepest increase in the plot of Z ?
 

Option: 1

xe

 


Option: 2

An


Option: 3

kn


Option: 4

Ne


Answers (1)

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Noble gases such as ve, Arr, the,kr found to deviate from ideal gas behaviour.
x gan will exhibit steepest increase in plot of z vs P.
Equation of state is given as -

\begin{aligned} P=\frac{R T}{(V-b)} &\mathrm{ \Rightarrow P(V-b)=R T }\\ &\mathrm{ \Rightarrow P V-P b=R T }\\ &\mathrm{ \Rightarrow \frac{P V}{R T}=1+\frac{P b}{R T} }\\ &\mathrm{ \Rightarrow z=\frac{P V}{R T} }\\ &\mathrm{ =1+\frac{P b}{R T} \Rightarrow y=c+m x}\\ \end{aligned}

 

Posted by

Pankaj Sanodiya

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