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At 25^{\circ} \mathrm{C}, a reversible isoentropic compression was performed on an ideal monoatomic gas to that the temperative reached 325^{\circ} \mathrm{C}. Find the value \mathrm{\ln p_2} if the \mathrm{1} mole of same gas was taken at an initial pressure of \mathrm{1} atm.

Option: 1

\mathrm{1.72\ atm}


Option: 2

\mathrm{0.172\ atm}


Option: 3

\mathrm{1.395\ atm}


Option: 4

\mathrm{2.0\ atm}


Answers (1)

best_answer

For isoentropic process, \mathrm{\Delta S_{sys}=0}
\mathrm{\therefore n c_p\ \ln \frac{T_2}{T_1}+n R\ \ln \frac{p_1}{P_2}=0}
\mathrm{\Rightarrow \frac{5}{2} R \ln \frac{598}{300}+R \ln \frac{1}{P_2}=0}
\mathrm{\begin{aligned} \ln \mathrm{P_2} & =\frac{5}{2} \ln \frac{598}{300} \\ & =1.72 \mathrm{~atm} \end{aligned}}
 

Posted by

sudhir kumar

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