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  • At a telephone enquiry system the number of phone calls regarding relevant enquiry follow Poisson distribution with a average of 5 phone calls during 10­-minute time intervals. The probability

At a telephone enquiry system the number of phone calls regarding relevant enquiry follow Poisson distribution with a average of 5 phone calls during 10­-minute time intervals. The probability that there is at the most one phone call during a 10-­minute time period is

Option: 1

\frac{6}{5^{e}}\;


Option: 2

\; \frac{5}{6}\;


Option: 3

\; \frac{6}{55}\;


Option: 4

\; \frac{6}{e^{5}}


Answers (1)

best_answer

P \left ( x; \mu \right ) = \frac{e^{-\mu\ \mu ^{x} }}{x}

Here\: X=1

\mu = 5

P\left ( 1;5 \right )-\frac{e^{5}\:5^{1}}{1}\: and \: P\left ( 0;5 \right ) - \frac{e^{-5}\:5^{0}}{0^{1}}

Required Probability = e^{-5}\left [ \frac{5}{1^{1}} +\frac{5^{0}}{0^{1}} \right ]

= \:e^{-5}\times 6

= \: \frac{6}{e^{5}}

Posted by

vinayak

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