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At 298 \mathrm{~K} \ and \ 1 bar, limestone was converted to time where \mathrm{\Delta H^{\circ}} and \mathrm{\Delta S^{\circ}} was \mathrm{198.3 \mathrm{~kJ} / \mathrm{mal}} and \mathrm{173.2\ \mathrm{JK}^{-1} \mathrm{~mol}^{-1}}, respectively. What will be the minimum temperature at which the conversion of limestone to lime will be spontaneous if temperature changes does not affect the \mathrm{\Delta H^{\circ}\ and\ \Delta S^{\circ}} values?

Option: 1

\mathrm{1145\ K}


Option: 2

\mathrm{1008\ K}


Option: 3

\mathrm{1118\ K}


Option: 4

\mathrm{1154\ K}


Answers (1)

best_answer

For a spontaneous rection, \mathrm{\Delta G} = negative
\mathrm{\begin{aligned} \Delta G^{\circ} & =\Delta H^{\circ}-T \Delta S^{\circ} \\ & \therefore \Delta H^{\circ}<T \Delta S^{\circ} \end{aligned}}
\mathrm{T>\frac{\Delta H^{\circ}}{\Delta S^{\circ}}>\frac{198.3 \times 10^{3}}{173.2}>1145}
 

Posted by

vishal kumar

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