Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • At moles of an ideal gas was upended isothermally. What will be the entropy c

At 256 \mathrm{~K}, 4 moles of an ideal gas was upended isothermally. What will be the entropy change if 24 \mathrm{~L} of the same expanded to the state where pressure becomes 1 atom.

Option: 1

\mathrm{-1.2\ cal/k}


Option: 2

\mathrm{1.2\ cal/ k}


Option: 3

\mathrm{13.85\ cal/k}


Option: 4

10.02\ \mathrm{cal/k}


Answers (1)

best_answer

\begin{aligned} P_1=\frac{n R T}{V_1} & =\frac{4 \times 0.0821 \times 256}{24} \\ & =3.5 \end{aligned}
\begin{aligned} \Delta S & =n R \cdot \ln \left(\frac{P_1}{P_2}\right) \\ & =4 \times 2 \ln \left(\frac{3.5}{1}\right) \\ & =4 \times 2 \times 2.303\ \log \left(\frac{7}{2}\right) \\ & =10.02\ \mathrm{cal/k} \end{aligned}

Posted by

Pankaj

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2026: JCECEB invites fresh applications for Jharkhand state merit list correction

Latest Question