Get Answers to all your Questions

header-bg qa

At room temperature, copper has free electron density of 8.4\times 10^{28}m^{-3}. The electron drift velocity in a copper conductor of cross-sectional area 10^{-6}m^{2} and carrying a current of 5.4 A, will be -

Option: 1

4\: ms^{-1}


Option: 2

0.4\: ms^{-1}


Option: 3

4\: cms^{-1}


Option: 4

0.4\: mms^{-1}


Answers (1)

best_answer

\begin{aligned} & \text { Use } \mathrm{i}=\text { ne } A \mathrm{v}_{\mathrm{d}} \\ & \therefore \mathrm{V}_{\mathrm{d}}=\frac{\mathrm{i}}{\mathrm{neA}} \end{aligned}

Posted by

Irshad Anwar

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE