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At time t=0 ,initial moles of A is 1 . Overall half life of the reaction is 10 days. Then calculate the number of mes of C after 30 days if the ratio of \mathrm{k_1: k_2: k_3 \ is \ 3: 2: 1.}

Option: 1

2 mol


Option: 2

1.46 mol


Option: 3

2.67 mol


Option: 4

3.33 mol


Answers (1)

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\mathrm{\text { Moles of } A \text { remain after } 30 \text { days }=\frac{N_0}{2^n}=\frac{1}{2^3}=\frac{1}{8}}

\mathrm{\left\{n=\frac{30}{10}=3\right\}}

\mathrm{\text { Moles of A converted to product }=1-\frac{1}{8}=\frac{7}{8} \mathrm{mol}}

\mathrm{\text { 5o, moles of } C=\frac{k_2}{k_1+k_2+k_3} \times \frac{7}{8} \times \frac{5}{1}=1.46 mol}

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Ajit Kumar Dubey

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