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Axis of solid cylinder of infinite length and radial R lies along y-axis it carries a uniformly distributed current ' i ' along ty direction. Magnetic field at a point \left(\frac{R}{2}, y, \frac{R}{2}\right) is :

Option: 1

\frac{\mu_0 i}{4 \pi R}(\hat{i}-\hat{k})


Option: 2

\frac{\mu_0 i}{2 \pi R}(\hat{j}-\hat{k})


Option: 3

\frac{\mu_0 i}{4 \pi R}\,\hat{j}


Option: 4

\frac{\mu_0 i}{4 \pi R}(\hat{i}+\hat{k})


Answers (1)

best_answer

  

Magnetic field visible cylinder =\frac{\mu_0 i r}{4 \pi R^2} \\

\because r=\frac{R}{2} \Rightarrow B=\frac{\mu_0 i}{4 \pi R}

Top view,  

\vec{B}=\frac{\mu_0 i}{4 \pi R}(\hat{i}-\hat{k})

 

Posted by

Pankaj Sanodiya

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