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BAC is any triangle described on the fixed base BC, and having a constant vertical angle; and BA is produced to P so as BP is equal to the sum of the sides containing the vertical angle. Find the locus of point P.

 

Option: 1

Straight line


Option: 2

circle


Option: 3

parabola


Option: 4

none of these


Answers (1)

best_answer

Given \mathrm{PB = AB + AC}

            \mathrm{PB = AB + PA}

       \mathrm{\Rightarrow PA = PC \Rightarrow < APC = < ACP = \alpha }

       \mathrm{\Rightarrow < BPC\Rightarrow < BAC=2\alpha } is constant

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shivangi.shekhar

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