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  • Block A is placed on the wedge A such that A remain contact with B as shown in figure. If the accelertaion of A is <img alt="\overline{a}_A= 5\widehat{i}+5\widehat{j}" src="/latex-image/?%5Cov

Block A is placed on the wedge A such that A remain contact with B as shown in figure. If the accelertaion of A is \overline{a}_A= 5\widehat{i}+5\widehat{j} then find the acceleration of B is:

 


 

Option: 1

\frac{3}{5}


Option: 2

\frac{5}{2}


Option: 3

\frac{2}{5}


Option: 4

\frac{5}{3}


Answers (1)

best_answer

For body to remian constant their relative acceleration perpendicular to surface is zero.

 

 

 

(a_A)_{\perp }=(a_B)_\perp

1= a_B \sin 37

a_B =\frac{5}{3}

=\left ( 5\times \frac{3}{5}-5\times \frac{4}{5} \right )=-1 = (a_A)_{\perp }

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Sayak

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