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Calculate the amount of charge on capacitor of 4 \mu \mathrm{F}. The internal resistance of battery is 1 \Omega:

Option: 1 4 \mu C  
Option: 2 8 \mu C
Option: 3 16 \mu C
Option: 4 Zero

Answers (1)

best_answer


At steady state, there will be no current in the branch with capacitor (capacitor fully charged)
I= \frac{5}{4+1}= 1A
V_{AB}= IR= 1\left ( 4 \right )= 4v
There is 2v potential drop across each capacitor
Q= CV= 4\times 10^{-6}\times \left ( 2 \right )
\Rightarrow Q= 8\mu c
The correct option is (2)

Posted by

vishal kumar

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