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Calculate the volume of \mathrm{Cl}_2(\mathrm{g}) that is produced in the time that is taken to liberate 8.0 litre of \mathrm{H}_2 in electrolysis of aqueous \mathrm{NaCl}.

Option: 1

4 L


Option: 2

8 L


Option: 3

2 L


Option: 4

1 L


Answers (1)

best_answer

\mathrm{No} \text {. of equivalent of } \mathrm{H}_2 =\mathrm{No} {\text {~of equivalent of } \mathrm{Cl}_2} \\

                              \frac{8 \times 1 }{22.4} \times 2 =\frac{\mathrm{VCl}_2}{22.4} \times 2 \\

                                       \mathrm{VCl}_2 =8 \mathrm{~L}

Posted by

Ritika Harsh

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