Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • Can someone explain - Chemical Bonding and Molecular Structure - JEE Main

The de Broglie wavelength of a tennis ball of mass 60g moving with a velocity of 10  metres per second is approximately

\left ( Planck'\! s \: constant, h= 6.63 \times 10^{-34}Js\right )

  • Option 1)

    10^{-33}metre

  • Option 2)

    10^{-31}metre

  • Option 3)

    10^{-16}metre

  • Option 4)

    10^{-25}metre

 

Answers (2)

best_answer

As we learnt in 

De-broglie wavelength -

\lambda = \frac{h}{mv}= \frac{h}{p}

- wherein

where m is the mass of the particle

v its velocity 

p its momentum

\lambda = \frac{h}{m\nu }= \frac{6.63\times 10^{-34}\times 1000}{60\times 10}m

    = 11.05\times 10^{-34}m= 1.105\times 10^{-33}metres

 Correct option is option 1

 


Option 1)

10^{-33}metre

Correct Option

Option 2)

10^{-31}metre

Incorrect option

Option 3)

10^{-16}metre

Incorrect option

Option 4)

10^{-25}metre

Incorrect option

Posted by

divya.saini

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2025 chemistry needs conceptual understanding; 5 tips to score high
anam-khan

JEE Main 2025 exam city intimation slip for session 1 soon; paper pattern, exams from January 22
anam-khan

JEE Main Maths 2025: Five tips to score high marks in ‘toughest’ subject; most important chapters

Latest Question