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  • Can someone help me with this, A mixture has 18g water and 414g ethanol. The mole fraction of water in mixture is (assume ideal behaviour of the mixture)

A mixture has 18g water and 414g ethanol. The mole fraction of water in mixture is (assume ideal behaviour of the mixture)

  • Option 1)

    0.1

  • Option 2)

    0.4

  • Option 3)

    0.7

  • Option 4)

    0.9

 

Answers (2)

best_answer

As we learned

 

Mole Fraction -

\dpi{100} Mole\: Fraction= \frac{Moles\: o\! f\: solute}{Moles\: o\! f solute+Moles\: o\! f solvent}

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 Molecular weight of  C_{2}H_{5}OH =24+5+16+1=46

Molecular mass of H_{2}O=18

414g of C_{2}H_{5}OH has \frac{414}{46}=9 mole

18g of HO_{2}=\frac{18}{18} = 1 mole

 Mole fraction of water =\frac{n_{1}}{n_{1}+n_{2}} = \frac{1}{1+9} = \frac{1}{10}=0.1


Option 1)

0.1

Option 2)

0.4

Option 3)

0.7

Option 4)

0.9

Posted by

Aadil

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0.1

Posted by

Priyank bisht

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