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A diver looking up through the water sees the outside world contained in a circular horizon.  The refractive index of water is \frac{4}{3} , and the diver’s eyes are 15 cm below the surface of water.  Then the radius of the circle is :

  • Option 1)

    15\times 3\times \sqrt{5}\: cm

  • Option 2)

    15\times 3\sqrt{7}cm

  • Option 3)

    \frac{15\times \sqrt{7}}{3}cm

  • Option 4)

    \frac{15\times 3}{ \sqrt{7}}cm

 

Answers (1)

best_answer

As we have learned

Radius of Circle of illuminance -

r=\frac{h}{\sqrt{\mu ^{2}-1}}

- wherein

 

 r = \frac{h}{\sqrt {\mu ^2 -1 }}

r = \frac{15}{\sqrt {({4/3}) ^2 -1 }}= \frac{15 \cdot 3}{\sqrt 7 }

 


Option 1)

15\times 3\times \sqrt{5}\: cm

Option 2)

15\times 3\sqrt{7}cm

Option 3)

\frac{15\times \sqrt{7}}{3}cm

Option 4)

\frac{15\times 3}{ \sqrt{7}}cm

Posted by

Avinash

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