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  • Can someone help me with this, The time of flight of a projectile on an upward inclined plane depends upon

The time of flight of a projectile on an upward inclined plane depends upon

  • Option 1)

    Angle of inclination of the plane 

  • Option 2)

    angle of projection

  • Option 3)

    value of acceleration due to gravity

  • Option 4)

    All of these

 

Answers (2)

best_answer

As we have learnt,

 

Projectile on an inclined plane -

Range along incline plane

R= \frac{2u^{2}.\sin \left ( \alpha - \beta \right )\cdot \cos \alpha }{g\cos^2 \beta }
 

- wherein

u=Speed of projetion

\alpha = Angle of projection above inclined plane

        (measured from horizontal line)

\beta = Angle of inclination.

 

 

Let Time of flight is T

\\*u_x = u\cos (\alpha - \beta) \\*u_y = u\sin(\alpha - \beta)

When ball will strike the inclined plane, its displacemnt along Y should be equal to zero.

\\*\Rightarrow y = 0 = u_y t - \frac{1}{2}a_y t^2 \\*\Rightarrow u\sin(\alpha-\beta)t -\frac{1}{2}\cdot g\cos\beta\cdot t^2 = 0 \\*\Rightarrow t = \frac{2u\sin(\alpha - \beta)}{g\cos\beta}


Option 1)

Angle of inclination of the plane 

Option 2)

angle of projection

Option 3)

value of acceleration due to gravity

Option 4)

All of these

Posted by

Plabita

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