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Circle \mathrm{x^2+y^2+4 x+2 y-4=0} is reflected in a line mirror and reflected circle have equation \mathrm{x^2+6 x+y^2+4 y+4=0}, then equation of mirror is

Option: 1

\mathrm{x+y+4=0}


Option: 2

\mathrm{2x-y=3}


Option: 3

\mathrm{x-2y=3}


Option: 4

\mathrm{x-y+4=0}


Answers (1)

best_answer

\mathrm{(x+2)^2+(y+1)^2=9 ;(x+3)^2+(y+2)^2=9}

so minor line is perpendicular bisector of line segment joining the centres.

\mathrm{\Rightarrow\left(y+\frac{3}{2}\right)=-\left(x+\frac{5}{2}\right) \Rightarrow x+y+4=0}

Posted by

rishi.raj

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