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Co-60 is a radioactive isotope. If 1 mg of { }^{60} \mathrm{Co} has an activity of 4.6 \times \mathrm{10^{12} \mathrm{~Bq}}, what is the half life of { }^{60} \mathrm{Co} (in hrs)?

Option: 1

360.67


Option: 2

416.67


Option: 3

390.33


Option: 4

450.5


Answers (1)

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\mathrm{\begin{aligned} \because A & =\lambda N \\ 4.6 \times 10^{12} B q & =\frac{\ln 2}{t_{1 / 2}} \times \frac{1 \times 10^{-3}}{60} \times 6 \times 10^{23} \\ t_{1 / 2} & =\frac{0.693 \times 6 \times 10^{20}}{4.6 \times 60 \times 10^{12}}=1.5 \times 10^6 \mathrm{~g} \\ t_{1 / 2} & =\frac{1.5 \times 10^6}{3600} \approx 416.67 \mathrm{hrs} \end{aligned}}

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vishal kumar

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