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coefficient of x5 in the expansion of (1+x^2)^5 (1+x)^2  is

Option: 1

10 


Option: 2

15 


Option: 3

20 


Option: 4

25 


Answers (1)

best_answer

As we have learned

Properties of Binomial Theorem -

Coefficient of x^{r} in the expansion of \left ( 1+x \right )^{n}\: is\: ^{n}c_{r}

 

- wherein

\left ( 1+x \right )^{n}\: :T_{r+1}= ^{n}c_{r}x^{r}

 

 

Coefficient of x5 in (1+x^2)^5 (1+x)^2 

                        = Coefficient of x5 in (1+5x^2+10x^4)(1+2x+x^2)  = 20

 

Posted by

Devendra Khairwa

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