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  • Confused! kindly explain, - Complex numbers and quadratic equations - JEE Main-10

ax^{2}+bx+c= 0 and x^{2}+2x+5= 0 have both roots common . Then minimum possible value of \left ( a+b+c \right )\left ( Where\; a,b,c\, \epsilon \, N \right ) is

  • Option 1)

    6

  • Option 2)

    8

  • Option 3)

    10

  • Option 4)

    12

 

Answers (1)

best_answer

\because  Both roots are common so , \frac{a}{1}=\frac{b}{2}=\frac{c}{5}

for minimum a+b+c:

a=1,b=2\; and \; \; c=5

 

Condition for both roots common -

\frac{a}{{a}'}=\frac{b}{{b}'}=\frac{c}{{c}'}
 

- wherein

ax^{2}+bx+c=0 &

a'x^{2}+b'x+c'=0

are the 2 equations

 

 


Option 1)

6

This is incorrect

Option 2)

8

This is correct

Option 3)

10

This is incorrect

Option 4)

12

This is incorrect

Posted by

Aadil

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