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  • Confused! kindly explain, - Complex numbers and quadratic equations - JEE Main-13

Let \alpha and \beta   be the roots of equation

x^{2}-6x-2=0.\; if a_{n}=\alpha ^{n}-\beta ^{n},\; for\: n\geq 1,\; then\; the \: value\; of\; \frac{a_{10}-2a_{8}}{2a_{9}}

is equal to:

  • Option 1)

    6

  • Option 2)

    -6

  • Option 3)

    3

  • Option 4)

    -3

Answers (9)

best_answer

x^2-6x-2=0\\ \alpha+\beta=6\\ \alpha.\beta=-2\\ Given, \frac{a_1_0-2a_8}{2a_9}, where a_n=\alpha^n-\beta^n\\ \frac{a_1_0-2a_8}{2a_9}=\frac{\alpha^1^0-\beta^1^0-2(\alpha^8-\beta^8)}{2(\alpha^9-\beta^9)}\\ Replace -2 with \alpha\beta\\ \frac{\alpha^1^0-\beta^1^0+(\alpha\beta)(\alpha^8-\beta^8)}{2(\alpha^9-\beta^9)}\\=\frac{\alpha^1^0-\beta^1^0+\alpha^9\beta-\alpha\beta^1^0}{2(\alpha^9-\beta^9)}\\ \frac{(\alpha+\beta)(\alpha^9-\beta^9)}{2(\alpha^9-\beta^9)}\\ =\frac{(\alpha+\beta)}{2}=\frac{6}{2}=3


Option 1)

6

Option 2)

-6

Option 3)

3

Option 4)

-3

Posted by

solutionqc

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3

 

Posted by

Banavathu Akash Naik

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3

Posted by

pradeepnain.

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probably option 3) 3

Posted by

ANIKET DAS

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3

Posted by

surya

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3

Posted by

akashvelaga6666

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3

Posted by

sushant varanasi

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3

Posted by

Anushika chauhan

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a

Posted by

Srilatha chavan

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