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  • Confused! kindly explain, - Complex numbers and quadratic equations - JEE Main-8

Number of +ve integer values of 'a' for which x^{2}+x+a=0  has roots of opposite sign is 

  • Option 1)

    0

  • Option 2)

    1

  • Option 3)

    2

  • Option 4)

    3

 

Answers (1)

best_answer

D> 0  &  \frac{c}{a}< 0\: \Rightarrow \, 1-4a> 0  &  \frac{a}{1}< 0

\Rightarrow \: a< \frac{1}{4}  &  a<0\: \Rightarrow a< 0

\therefore Option (A)

 

Roots are of opposite sign -

\frac{c}{a}< 0,D= b^{2}-4ac> 0

-

 

 


Option 1)

0

This is correct

Option 2)

1

This is incorrect

Option 3)

2

This is incorrect

Option 4)

3

This is incorrect

Posted by

Himanshu

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