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An electric charge 10^{-3}\mu C  is placed at the origin (0,0)of  X-Y co-ordinate system . Two points A and B are situated at \left ( \sqrt{2},\sqrt{2} \right )\: and\: \left ( 2,0 \right ) respectively. The potential difference between the point  A and B will be

  • Option 1)

    4.5 volt

  • Option 2)

    9 volt

  • Option 3)

    zero

  • Option 4)

    2 volt

 

Answers (2)

As we learnt in

Potential Difference -

V_{B}-V_{A}=\frac{w}{q}

-

 

 \vec{r_{1}}= \sqrt{2}\hat{i}+\sqrt{2}\hat{j}

\left | \vec{r_{1}} \right |= r_{1}= \sqrt{\left ( \sqrt{2} \right )^{2}+\left ( \sqrt{2} \right )^{2}}= 2

\vec{r_{2}}= 2\hat{i}+0\hat{j}

or \left | \vec{r_{1}} \right |= r_{2}= 2

Potential \: at\: point\: A\: is\:

V_{A}= \frac{1q}{4\pi \varepsilon _{0}r_{1}}

= \frac{1}{4\pi \varepsilon _{0}}\frac{10^{-3}\times 10^{-6}}{2}

Potential\: at\: point\: B \: is \:

V_{B}=\frac{1}{4\pi \varepsilon _{0}}\frac{q}{r^{2}}= \frac{1}{4\pi \varepsilon _{0}}\frac{10^{-3}\times10^{-6} }{2}

\therefore V_{A}-V_{B} = Zero


Option 1)

4.5 volt

Incorrect

Option 2)

9 volt

Incorrect

Option 3)

zero

Correct

Option 4)

2 volt

Incorrect

Posted by

Sabhrant Ambastha

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