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  • Confused! kindly explain, Four capacitors of each of capacity 3μFare connected as shown in the adjoining figure. The ratio of equivalent capacitance between A and B and between A and C will be

Four capacitors of each of capacity 3μFare connected as shown in the adjoining figure. The ratio of equivalent capacitance between A and B and between A and C will be

 

  • Option 1)

    4:3

  • Option 2)

    3:4

  • Option 3)

    2:3

  • Option 4)

    3:2

 

Answers (2)

best_answer

As we learnt in 

Series Grouping -

\frac{1}{C_{eq}}=\frac{1}{C_{1}}+\frac{1}{C_{2}}+\cdots

- wherein

 

 and

Parallel Grouping -

C_{eq}=C_{1}+C_{2}+\cdots

- wherein

 

 Between A and B, 3 capacitors are in series and they are in parallel with capacitance between A and B.

C_{1} = \frac{C\times 3C}{C+3C} = \frac{3C}{4}

Between A and C:

Two capacitors are in series and in turn they are parallel.

C_{2} = \frac{2C\times 2C}{2C+2C} = C

Ratio = \frac{3}{4}


Option 1)

4:3

Incorrect

Option 2)

3:4

Correct

Option 3)

2:3

Incorrect

Option 4)

3:2

Incorrect

Posted by

prateek

View full answer

its wrong the option should be first one

 

 

Posted by

Visesh

View full answer

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